Before we start with today’s article, something needs to get engraved in your minds. If some current goes out somewhere, it will always come back to the source, with no exceptions. Hence, there is always a current loop, a current return path along with the current-carrying traces. So, the current does not really care if you provide it that return path, it will find its own. But if you do not, it will interfere and mess around with your entire circuit, while finding its own way back.

**What Is a Current Return Path and Why Does the Current Return?**

The return path of current is nothing but the path the current takes to return to the source. Do you remember what an electrical circuit is? It is a path through which electrons flow from a voltage or current source. The ‘source’ of electrons is the point where those electrons enter the circuit. And the point where electrons leave an electrical circuit is called the ‘return’ or ‘ground’. Since electrons always end up at the source when they complete the path of their circuit, we call the exit point ‘return’.

The answer to ‘why’ is simple: the consequence of charge conservation and also conservation of energy. Suppose the current does not return to the source. Then what? The charge will still build up in someplace. There will be an excess of (+) charge at a place and an excess of (-) charge somewhere else. That disturbance would cause potential differences that would, in turn, make the current want to flow backward. Remember Kirchhoff’s Law (1st Law)?

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Kirchhoff’s current law states that the current flowing into a node (or a junction) must be equal to the current flowing out of it. In other words, the algebraic sum of ALL the currents entering and leaving a node must be equal to zero, such as:

**I(exiting) + I(entering) = 0**

Therefore, if the net flow of charge in and out of every node every component in a circuit is zero, then it implies the current must return to its source, no matter what the circuit.

If the current flows in loops and returns to the source, you would expect the current to travel to the end of the line and flow back down the return path. But how long does this entire process take? When can you see the current come out of the return path? Does it take 2 seconds? 1 second to go down and 1 second to come back? If there is an insulating dielectric material between the signal and return conductors, how could the current possibly get from the signal to the return conductor, except at the far end?

Let’s start by thinking in the basic model, the line through which the current flows, let that be a bunch of tiny capacitors. The initial current flow into the line, as the signal launches, it sees the capacitor. If the voltage across the capacitor is constant, the current will not flow. As the signal enters the transmission line, there is a voltage build-up across the signal and return path. During this transition time, as the edge passes by, the voltage changes and the current flows through the initial capacitor. When the signal is launched, it has no idea how you have planned its entire trip, and it does not matter. The to and fro motion of the current is absolutely dependent on the immediate environment and the region of the line where the voltage is changing—that is, where the signal edge is.

The source current flows into the conductor, and through displacement current passes through the capacitance between the signal and return path, and out of the return path. This is the loop. As the voltage transition-edge propagates through the line, the current loop also propagates through the transmission line. We can extend the transmission line model to include the rest of the signal and return paths with all the various distributed capacitors between them. Given that the signal voltage is changing.

Anything that disrupts the current loop will disrupt the signal and cause a distortion in the impedance, compromising signal integrity.

**Routing the Return Path Deliberately!**

Many people imagine changes in a circuit occur immediately, as you switch on a circuit and the light shines in just a click. It is quite easy to have a misconception because the change in the state exceeds human perception.

But in reality, when an ‘alternating current’ passes through in the circuit, an electric field is set up in the areas. These field lines will then spread through the surrounding conductors and maybe transfer to nearby circuits as well. Along with this, your circuit faces a change of state that in turn gives rise to an electric potential and hence the current pass through the circuit. This electric field generates an electromagnetic field around the conductor the current flows through. Changes in the electromagnetic field propagate very fast but at a finite speed, and it takes some time for the changes in the field to reach the far ends of your circuit. Therefore, it is possible for two ends of a trace to be in two different states, with a transition point that moves along the length. This will give rise to unwanted currents in nearby conductors.

Not only that poor routing can lead to noises in the circuit, which in turn will create issues in electromagnetic compatibility, susceptibility and create electromagnetic interference. Hence, degrading the overall circuit performance.

**Why Is Current Return Path Vital in PCB Design?**

Yesteryear’s electronic design was kind of considerate. Somewhat bad schematics and not so efficient layout would still produce some meaningful and functional boards. But now, in the race to make PCBs and chips smaller, the operating voltages and their noise margins are getting reduced. The reduction is in such a manner that the engineers now need to be extra mindful of their design choices.

Not only smaller but PCBs are now getting faster. Now, PCBs are intended to operate at frequencies high enough to significantly degrade circuit performance. Those are called high-speed PCBs. Other factors include: the materials, the length of the traces along with the size of the board, and also the environment. Though, traditionally, 50 MHz and above is the point where a PCB layout can be considered a high-speed PCB design. Another interesting aspect of high-speed PCBs is such that they don’t follow the path of least resistance; they follow the path of least impedance. Without a proper return path layout, you might find yourself with currents spreading around splits in your ground plane, and in turn leading to a loss of signal integrity.

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**High-Speed PCBs and Current Return Path**

No matter how much experience you have, you could forget about the fact that impedance may look like resistance. But it’s not. It is a generic expression that accounts for time and frequency dependency. It is a complex quantity with an imaginary (reactance) part and a real (resistive) part.

So, you may tend to ignore the reactive part of impedance in your circuit return paths and focus strictly on the resistive. With the increase in frequency along with depreciation in rise/fall time, the reactive part of impedance becomes more important in return paths.

In some cases, the return path of the current flows directly underneath the conductor. Therefore, you should provide a desirable path before a less desirable path is established in your circuit.

Now let’s go ahead with how a **high-speed PCB** current return routing is done.

Suppose you have a double-sided board, a single trace on top and a full copper ground plane at the bottom. The board has two vias that connect the trace with the ground plane. Upon reaching its desired point, it travels to the ground plane through the via and ends up at its source.

But the question here is how? The current can return in three given paths: the easiest known path is to trace back the way of its flow, the direct path. Or, it can travel in a loop, the least area loop. It is underneath the top trace. Otherwise, it can combine both the ways to travel back to its source.

As you already know by now, current returns to the source through the least impedance path.

We know that the impedance (Z) of a resistor equals the value of the resistor (R), such as:

**Z = R**

Again, the magnitude of the impedance in an inductor is:

**|Z| = ω.L**

In the frequency domain, we can express the impedance of an inductor as:

**Z = j.ω.L**

Therefore, using the lumped-parameter circuit theory impedance we can find the ground impedance Zg.

**Zg = Rg + jωLg**

Where** Rg** and** Lg** are the ground path resistance and inductance, respectively.

For low frequencies, the ground current takes up the path of least resistance. It traces back the path to the source. Here, this is also the path of the lowest impedance.

For high frequencies, the ground current will follow the route of least inductance. This is directly underneath the trace because this represents the smallest loop area.

At low frequencies (1 – 100 kHz), the return current flows majorly through the direct path of the least resistance. As the frequency increases to 500 – 1,000 kHz, the current splits between the two paths of the least resistance and least inductance. At high frequencies (10 – 100 MHz), the majority of the return current flows underneath the top trace through the path of least inductance.

For higher-frequency signal traces, a differential pair is used. The reason for this is simple: the differential pairs carry both the signal and the opposite phase of the signal. Hence, the radiations get canceled and the current flowing is zero. Therefore, they can combat common mode noise or induced noise. Careful and deliberate planning of a ground return path will keep unwanted currents from forming in parts of your circuit where they should not be.

**Return Path Discontinuities **

Until now, whatever we discussed were the cases of a solid ground plane. But there can be situations where there is a discontinuity in the ground plane. While designing for return paths, you should also keep in mind cases of cutouts, slots or maybe clearance holes. Suppose there is a slot in the ground plane, what do you think can go wrong?

This is kind of conventional that a solid and uninterrupted return path would have a better electromagnetic capability. The current would go along a closed-circuit loop, hence making the resultant current zero. The loop is small/narrow enough; also, the return path of via microstrip is just beneath the plane of a signal trace.

But discontinuities in the return path will give rise to noises. Cutouts, slots or even clearance holes for through-hole or vias, all of these can cause a discontinuity in the return path. It creates a larger current loop area. This results in an increase in loop inductance. Hence, the current will spread out, and might also get at the edges forming an antenna. The clearance holes are less of a threat to the current flow. Unless the holes overlap, there is not much of an issue.

Everything that affects the signal current or the return current path will affect the impedance of the signal. Therefore, the return path should be designed just as carefully as the signal path, no matter if it is on a PCB, a connector, or an IC package.

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This information is priceless. When can I find out more?

Would you kindly share this info in pdf? That would be much appreciated.. Thanks a lot

It’s hard to find knowledgeable people on this topic, but you sound like you know what you’re talking about! Thanks